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1vote
1answer
134views

Minimizing the absolute value of a line integral over a non-conservative vector field

I have heard the comparison between line integrals and work, so how would I minimize the absolute value of the line integral of two points over a non-conservative vector field (if it were conservative,...
Madeline Jaccon's user avatar
1vote
1answer
140views

Exact test for checking conservative forces

What is the nature of this force on the path $x^2+y^2=1$? $$\tag1\vec F=\frac{-y\,\hat{i }+x\,\hat{j}}{x^2+y^2}.$$ I tried two methods, but they give different answers: For this specific path it ...
Maths's user avatar
10votes
5answers
2kviews

Intuition for vector calculus identities

I can follow the proofs for these identities, but I struggle to intuitively understand why they must be true: $$$$ 1. The curl of a gradient of a twice-differentiable scalar field is zero: $$\nabla\...
TunaSandwich's user avatar
3votes
3answers
2kviews

Why is the work done non-zero even though it's along a closed path?

So, in this problem I just solved there is a force field given by $\mathbf{F} = -x \hat{\mathbf{j}}$ and I need to compute the work done on a particle along a circular path of radius $R$, centred at ...
Dewd's user avatar
0votes
1answer
71views

How do force-fields (i.e. electric field) apply "force at a distance"?

I often see when an article or text describes a "field of force" (for this question lets use the electric field) that they say that its a "forces at a distance". Whats going on ...
Jake's user avatar
  • 113
2votes
1answer
228views

What is the vector field associated with potential energy?

The mere concept of a line integral is defined for a vector field, and I thus thought the following was a rigorous and general definition of potential energy: Definition: Given a conservative force ...
Sam's user avatar
  • 379
-1votes
1answer
48views

Conservation and potential with non-cartesian forces

I understand how to determine if a force is conservative from \begin{equation} \nabla\times \mathbf{F}=0 \implies \mathbf{F}\text{ is conservative} \end{equation} When $F$ is in cartesian coordinates. ...
21kondav's user avatar
0votes
1answer
681views

Gravitational field strength between equipotential lines

Is the gravitational field strength between two equipotential lines the same at all distances? For example, in the image, does point P experience the same gravitational field strength as a point ...
Blue Green's user avatar
0votes
2answers
823views

Intuition behind a line integral over a vector field

I have seen answers to this question on this site already, though I still do not understand what line integrals and there results represent and would appreciate an oversimplified description. I have ...
Diaz.Mrn's user avatar
0votes
0answers
87views

Find the curl if the vector field depends on a parameter

Given the following vector, \begin{align} F(x(t),y(t),z(t)) &= \begin{bmatrix} \omega_1^2 x_o\cos(\omega_1 t) \\ \omega_2y_0\sin(\omega_2 t)\\ 0\\ \...
user996159's user avatar
0votes
1answer
78views

Can anyone tell me how does conservative forces work? Confused

From vector calculus, I'd learnt that a conservative vector field satisfies $$ \textbf{F} = \boldsymbol{\nabla} g $$ which $\textbf{F}$ is the gradient of some scalar-valued function, and $g$ is the ...
I'm a lightbulb's user avatar
1vote
4answers
662views

Why isn't the magnetic field defined by the magnetic force on a particle moving through it?

A magnetic field describes the influence a charge (in motion) experiences. In other words, it is essentially a vector field that describes the force that a particle will feel at a given location. ...
Bigbarbadboybabyboobae's user avatar
2votes
3answers
767views

Why can a force field only be conservative if it is spherically symmetric?

I saw in my textbook that a field can only be conservative if it happens to be spherically symmetric. Why is this so? Is there a good proof for this?
user avatar
1vote
1answer
442views

The curl of a friction force being zero

Consider the resistive force modelled by the function $\vec{F} = -b\vec{v}(t)$. The curl of this function, $\nabla \times \vec{F}$, is $$[\frac{\partial}{\partial y} (\frac{dz}{dt}) - \frac{\partial}{\...
abouttostart's user avatar
0votes
2answers
403views

Force through potential energy: does the absolute value of energy has sense?

Force can be found from potential energy: $$\vec{F}=-\nabla U$$ In other words, force depends on how the potential energy changes in space, but not on the potential energy value? Or if we take ...
bcubeu26dncs's user avatar

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